6y^2-40y-64=0

Solution for 6y^2-40y-64=0 equation:

6y^2-40y-64=0

a = 6; b = -40; c = -64;
Δ = b2-4ac
Δ = -402-4·6·(-64)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-56}{2*6}=\frac{-16}{12}
=-1+1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+56}{2*6}=\frac{96}{12}
=8
$